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60=x^2-6x+5
We move all terms to the left:
60-(x^2-6x+5)=0
We get rid of parentheses
-x^2+6x-5+60=0
We add all the numbers together, and all the variables
-1x^2+6x+55=0
a = -1; b = 6; c = +55;
Δ = b2-4ac
Δ = 62-4·(-1)·55
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-16}{2*-1}=\frac{-22}{-2} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+16}{2*-1}=\frac{10}{-2} =-5 $
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